-y^2+4y=16

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Solution for -y^2+4y=16 equation: 



-y^2+4y=16

We move all terms to the left:

-y^2+4y-(16)=0

We add all the numbers together, and all the variables

-1y^2+4y-16=0

a = -1; b = 4; c = -16;
Δ = b2-4ac
Δ = 42-4·(-1)·(-16)
Δ = -48
Delta is less than zero, so there is no solution for the equation

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